Answer:
Option A applies the Commutative Property of Multiplication; ( 4 + 2i )( 3 - 5i ) to ( 3 - 5i )( 4 + 2i )
Explanation:
Option A; We can see that this equation applies the commutative property of addition, provided it alters two terms, 4 and 2i, from the position ( 4 + 2i ) to ( 2i + 4 )
Option B; Here we apply the commutative property of multiplication, where the expressions in the equation are grouped such that they are interchanged to not change the value of the expressions, ( 4 + 2i )( 3 - 5i ) to ( 3 - 5i )( 4 + 2i )
Option C; The identity property takes it's place such that it multiplies the expression ( 4 + 2i )( 3 - 5i ) by 1 so that the expression's value doesn't change, ( 4 + 2i )( 3 - 5i ) to ( 4 + 2i )( 3 - 5i )( 1 )
Option D; The additive property of zero states that if you add zero to an expression, in this case ( 4 + 2i ), it's value doesn't change ⇒
( 4 + 2i ) = ( 4 + 2i + 0 )
Answer; Option A applies the Commutative Property of Multiplication; ( 4 + 2i )( 3 - 5i ) to ( 3 - 5i )( 4 + 2i )