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3 votes
PLEASE HELP!!!

Given: △EIJ, k(O, r)

EI = EJ = r=10 cm

EP ⊥ IJ

Find: JP

User Andwjstks
by
6.9k points

1 Answer

4 votes

Answer:


h=(10√(3))/(2)=5√(3)\ cm.


JP=5√(3)\ cm

Explanation:

Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.

Since EP⊥IJ, then segment JP is the height of the triangle EOJ.

The height of the equilateral triangle can be found using formula


h=(a√(3))/(2),

where a is the side length.

So,


h=(10√(3))/(2)=5√(3)\ cm.

Therefore JP is 5√3 cm

User Erick Ribeiro
by
6.8k points