Question

Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4.

Answer 1

y = -13x + 55

Explanation:

perpendicular formula : m1 × m2 = -1

y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

m = -13 point = ( 4 , 3 )

sub them into the formula,

3 = -13 (4) + c

3 = -52 + c

3 + 52 = c

55 = c

c = 55

now we rewrite again the c and the m to become a complete equation : y = -13x + 55