Question

An electric kettle supplies 20,000J of energy to heat 0.5kg of water. What is the temperature change? The specific heat capacity of water is 4200J/kg°C.

Answer 1

The change in temperature is 9.52°C

Step-by-step explanation:

Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.

Thus, from the law of conservation of energy can be stated as:

Heat Supplied by Electric Kettle = Heat Absorbed by Water

Heat Supplied by Electric Kettle = m C ΔT

where,

Heat Supplied by Electric Kettle = 20,000 J

Mass of water = m = 0.5 kg

Specific Heat Capacity of Water = C = 4200 J/kg.°C

Change in Temperature of Water = ΔT

Therefore,

20,000 J = (0.5 kg)(4200 J/kg.°C) ΔT

ΔT = 20,000 J/(2100 J/°C)

ΔT = 9.52°C