2.2k views
3 votes
Which statement is true about the extreme value of the given quadratic equation? A. The equation has a maximum value with a y-coordinate of -21. B. The equation has a maximum value with a y-coordinate of -27. C. The equation has a minimum value with a y-coordinate of -21. D. The equation has a minimum value with a y-coordinate of -27.

User Hzpz
by
5.2k points

1 Answer

3 votes

Answer:

A. The equation has a maximum value with a y-coordinate of -21.

Explanation:

From the given equation:


\mathbf{y = -3x^2 + 12x -33}

This parabola is vertical and is goes downward via the negative path

Where the vertex represents the maximum value;


\mathbf{y = -3 (x^2 + 4x) -33}

Using completing the square method;


\mathbf{y = -3 (x^2 + 4x+2^2) -33+12}


\mathbf{y = -3 (x^2 + 4x+4) -21}

To perfect square:


\mathbf{y = -3 (x-2)^2 -21}

The vertex point is (2, -21)

Hence ; the equation has a maximum value with a y-coordinate of -21.

User Sylvain Rodrigue
by
3.7k points