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What is the diameter of a sphere with a volume of 498 in3, to the nearest tenth of an inch

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Answer:

9.8 inches

Explanation:

Formula for volume of the sphere is = 4/3πr³

Form and solve the equation for the radius

So: 4/3πr³= 498in³

πr³= 498in³*3/4 which = to 373.5in³

r³= 373.5in³/π

r=∛(373.5in³/π)

calculate r and times the result by 2 for diameter

it will be 9.834...

nearest tenth of an inch means the accuracy is 1 decimal place because nearest tenth= 1/10 or 0.1

So the final answer is 9.8in

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