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What is the diameter of a sphere with a volume of 498 in3, to the nearest tenth of an inch
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Sep 9, 2021
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What is the diameter of a sphere with a volume of 498 in3, to the nearest tenth of an inch
Mathematics
high-school
Mathieu Garstecki
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Mathieu Garstecki
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Answer:
9.8 inches
Explanation:
Formula for volume of the sphere is = 4/3πr³
Form and solve the equation for the radius
So: 4/3πr³= 498in³
πr³= 498in³*3/4 which = to 373.5in³
r³= 373.5in³/π
r=∛(373.5in³/π)
calculate r and times the result by 2 for diameter
it will be 9.834...
nearest tenth of an inch means the accuracy is 1 decimal place because nearest tenth= 1/10 or 0.1
So the final answer is 9.8in
Incpetor
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Sep 13, 2021
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Incpetor
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