Question

URGENT!!

Find the area of a triangle to the nearest square centimeter, where a=3cm, b=5cm, and m∠C=53°

A. 5 cm²
B. 6 cm²
C. 9 cm²
D. 12 cm²

Answer 1

Option B will be the answer.

Explanation:

From the figure attached,

ABC is a triangle having ∠C = 53°, a = 3 cm and b = 5 cm

Since area of a triangle =
`(1)/(2)(\text{Base})(\text{height})`

=
`(1)/(2)(BC)(AE)`

SinC =
`(AE)/(AC)`

Sin53° =
`(AE)/(5)`

AE = 5(sin53°)

= 3.993

Now area of triangle ABC =
`(1)/(2)(3.993)(3)`

= 5.99

≈ 6 square cm

Therefore, area of ΔABC = 6 cm²

Option B will be the answer.