Question

What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?

Answer 1

`T = 0.182` Kelvin

Step-by-step explanation:

As we know that

`PV = nRT\\`

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin

R is the gas constant

V is the volume in liters

`R = 0.08206`

Substituting the given values in above equation, we get -

`1.35 * (50)/(1000)= 4.5 * 0.08206* T\\`

On rearranging, we get

`T = (1.35*50)/(1000*0.08206*4.5) \\`

`T = 0.182` Kelvin