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In the diagram shown points A, B, C, D, and E lie on circle M. Point P is on the exterior or circle M and secants PCD and PBE drawn. It is known that m

(a) Determine the measure of BC


(b) Determine the measure of

User Jokab
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1 Answer

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Answer:

The measure of
m \hat {BC}=34^0

The measure of
\angle DFE = 81^0

Explanation:

The correct question is added in the diagram below.

From the diagram;

Given that:

∠A = 55°

∠P =38°


m \hat {AC} = 86^0


m \hat{DE} = 2( \angle A )


m \hat{DE} = 2( 55^0 )


m \hat{DE} = 110^0

a) it is clear and obvious that ∠P is formed at the exterior of the circle; so:


m \angle P = \frac{m \hat {DE} -m \hat {BC} }{2}


38= \frac{110 -m \hat {BC} }{2}


38*2={110 -m \hat {BC} }{


76={110 -m \hat {BC} }{


m \hat {BC} }{={110 -76


m \hat {BC}=34^0

b)
m \hat {AC}=m \hat {AB}+ m \hat {BC}


86=m \hat {AB}+ 34


m \hat {AB}=86-34


m \hat {AB}=52


\angle DFE = \frac{m \hat{DE}+m \hat{AB}}{2} (rule: chord intersecting inside the circle)


\angle DFE = (110+52)/(2)


\angle DFE = (162)/(2)


\angle DFE = 81^0

In the diagram shown points A, B, C, D, and E lie on circle M. Point P is on the exterior-example-1
User AJ Venturella
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