Answer:
Null hypothesis: H0 = 0.57
Alternative hypothesis: Ha ≠ 0.57
z = -11.08
P value = P(Z≠-11.08) = 0.00001
Decision we reject the null hypothesis and accept the alternative hypothesis. That is, parents feel differently today than they did twenty years ago
Rule
If;
P-value > significance level --- accept Null hypothesis
P-value < significance level --- reject Null hypothesis
Z score > Z(at 90% confidence interval) ---- reject Null hypothesis
Z score < Z(at 90% confidence interval) ------ accept Null hypothesis
Explanation:
Given;
n=800 represent the random sample taken
Null hypothesis: H0 = 0.57
Alternative hypothesis: Ha ≠ 0.57
Test statistic z score can be calculated with the formula below;
z = (p^−po)/√{po(1−po)/n}
Where,
z= Test statistics
n = Sample size = 800
po = Null hypothesized value = 0.57
p^ = Observed proportion = 301/800 = 0.376
Substituting the values we have
z = (0.376-0.57)/√(0.57(1-0.57)/800)
z = −11.0834525873
z = -11.08
To determine the p value (test statistic) at 0.10 significance level, using a two tailed hypothesis.
P value = P(Z<-11.08) = 0.00001
Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = -11.08) which doesn't falls with the region bounded by Z at 0.10 significance level. And also the two-tailed hypothesis P-value is 0.00001 which is lower than 0.10. Then we can conclude that we have enough evidence to FAIL or reject the null hypothesis, and we can say that at 10% significance level the null hypothesis is invalid, therefore we accept the alternative hypothesis.