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What is the range of the function y= ^3 sqaure root x+8?
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What is the range of the function y= ^3 sqaure root x+8?

User JustinB
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1 Answer

4 votes

Answer:

-∞≤y≤∞

Explanation:

The given function is

y=(x+8)^{\frac{1}{3}}

Taking cube on both sides

y^3=x+8\\\\x=y^3-8

Hope this helps.

User BartDur
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