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What equation of a circle has a center of (3,-2) and a radius of 9

1 Answer

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Answer:


(x-3)^2 + (y+2)^2 = 81

Explanation:

Center of the circle = (3, -2)

therefore h = 3, k = - 2

Radius (r) = 9

Equation of circle in center radius form is given as:


(x-h)^2 + (y-k)^2 = r^2\\(x- 3)^2+ \{y-(-2)\}^2 = 9^2\\\huge\red{\boxed{(x-3)^2 + (y+2)^2 = 81}}\\this\: is \:the \:required\: equation\: of\: the\: circle.

User Syed Tayyab Ali
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