Question

2. Write the standard equation of the circle.

Center (5, -1); r = 12
A) (x-5)^2 +(y- 1)^2 = 12
B) (x-5)^2 +(y + 1)^2 = 12
C) (x-5)^2 +(y - 1)^2 = 144
D) (x-5)^2 +(y +1)^2 = 144

Answer 1

D

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - 1)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (5, - 1 ) and r = 12, thus

(x - 5)² + (y - (- 1))² = 12² , that is

(x - 5)² + (y + 1)² = 144 → D