Question

Ther are twi factors of -36 such that one factor is 11 less than half of the other factor.

Answer 1

The 2 factors are -2 and 18.

Explanation:

xy = -36

Let y = 0.5x - 11 so

x(0.5x - 11) = -36

0.5x^2 - 11x + 36 = 0

0.5(x^2 - 22x + 72) = 0

(x - 4)(x - 18) = 0

x = 4, 18.

Try x = 18:-

The 2 numbers which are factors of -36 must be -2 and 18 because they fit the requirement that 0.5(18) - 11 = 9 - 11 = -2.