Question

In ΔABC, the measure of ∠C=90°, the measure of ∠A=64°, and AB = 2.7 feet. Find the length of BC to the nearest tenth of a foot.

Answer 1

BC=AB x sinA=2.7 x sin64'=2.4

Answer 2

Applying sine theorem for right triangle ABC, we have:

sin A = BC/AB

=> BC = AB x sin A = 2.7 x sin(64 deg) = ~2.4 (ft)

Hope this helps!

:)