Question

In a certain Algebra 2 class of 28 students, 23 of them play basketball and 12

of them play baseball. There are 3 students who play neither sport. What is
the probability that a student chosen randomly from the class plays both
basketball and baseball?

Answer 1

5/14

Explanation:

P(A or B) = P(A) + P(B) − P(A and B)

25/28 = 23/28 + 12/28 − P(A and B)

P(A and B) = 10/28

P(A and B) = 5/14