Question:
Vincent bought a 25-pound bag of rice. He cooked 6.25 pounds of the rice. He stored the rest of the rice in
- pound portions. What is the maximum number of
- pound portions he stored?
Answer:
The maximum number of portion he stored is 5 portion
Explanation:
Given
Size of Rice = 25 lb
Size of Cooked Rice = 6.25 lb
Portions saved =
lb
Required
Number of portion saved;
First, the size of rice after cooking needs to be calculated;
If 6.25lb of rice was cooked from a total of 25lb;
Then, the size of rice left is
![Size = 25lb - 6.25lb](https://img.qammunity.org/2021/formulas/mathematics/high-school/iy7iarailr4tmklyfkdwyqufa1xrwmf30u.png)
![Size = 18.75lb](https://img.qammunity.org/2021/formulas/mathematics/high-school/t845ag7at3dgmayzbp7alf8cl0hqfu1xhi.png)
Now that we have the amount left after cooking; we can simply calculate the maximum number of portions;
This is calculated by dividing size of rice left by portions of saved rice;
i.e.
Maximum number of portion = Size of rice left / Portions of saved rice
Maximum number of portion =
![(18.75lb)/(3(3)/(4)lb)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ib2nfoz3jcm7ngq09vvaah8qw8ab3ysan4.png)
Convert
to mixed fraction
Maximum number of portion =
![(18.75lb)/((15)/(4)lb)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3wc669pnk19h8hl28glmshy6znd0stb7tt.png)
Maximum number of portion =
![(18.75)/((15)/(4))](https://img.qammunity.org/2021/formulas/mathematics/high-school/ns3e6mm6jvkjtga5bqdyos7o6tgrhcprq9.png)
Rewrite expression
Maximum number of portion =
![18.75 / (15)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dr82lkpiom3oz0z6823tadnm5aj82fywsh.png)
Change divide (/) sign to multiplication (*)
Maximum number of portion =
![18.75 * (4)/(15)](https://img.qammunity.org/2021/formulas/mathematics/high-school/83apwmhzoq2zvuv6rseap7dqtxjs3ramob.png)
Maximum number of portion =
![(75)/(15)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hs6kohigommc6nisisz7iw0me55i2b4pvs.png)
Maximum number of portion = 5
Hence, the maximum number of portion he stored is 5 portions