Answer: (-31.09 mi, -20.97 mi)
Explanation:
If the noon is our initial time, then we have that 2:30 pm is t = 2.5 hours.
Now, the position (x, y) of the ship can be writen as:
(velocity*time*cos(angle), velocity*time*sin(angle))
or:
(15mph*t¨*cos(214°), 15mph*t*sin(214°))
then the position at t = 2.5 hours is:
(15mph*2.5h*cos(214°), 15mph*2.5h*sin(214°))
(-31.09 mi, -20.97 mi)