Question

6) What is the pressure in atmospheres exerted by a 0.500 mol sample of

nitrogen gas in a 10.0 L container at 298 K? (KEEP 3 SIG FIGS; DO NOT TYPE
ANY UNITS)*

Answer 1

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Step-by-step explanation:

Answer 2

1.22 atm

Explanation:

Use the Ideal Gas Law, PV=nRT to solve. If you rearrange the equation to solve for P, you get P=nRT/v. Plug in the values to solve, like so:

P=(0.500)(0.0821)(298)/(10.0)

When solved, the equation gives you 1.22329. Round to three significant figures to get your answer of 1.22 atm.