Question

What is the Area of the Trapiziod ABCD

Answer 1

From the figure given we know that the lower base measures 7+7 = 14 representing the distance between the point B and C

For the upper base the distance between the point A and D is 5+3 = 8

The height can be founded from the distance between the point A and the lower base and we see that the hight is
`h = 5+4 =9`

Then the area can be founded with this formula:

`A = (AD+ BC)/(2) *h`

And replacing we got:

`A = (8+14)/(2) *9 = 99 units^2`

Explanation:

We can olve the problem with this way much easier.

From the figure given we know that the lower base measures 7+7 = 14 representing the distance between the point B and C

For the upper base the distance between the point A and D is 5+3 = 8

The height can be founded from the distance between the point A and the lower base and we see that the hight is
`h = 5+4 =9`

Then the area can be founded with this formula:

`A = (AD+ BC)/(2) *h`

And replacing we got:

`A = (8+14)/(2) *9 = 99 units^2`