Question

Identify the center and radius for the equation x ^ 2 + (y - 3) ^ 2 = 4

Answer 1

r = 2. The center is at (0, 3).

Explanation:

Compare the given x ^ 2 + (y - 3) ^ 2 = 4 to the standard equation

(x - h)^2 + (y - k)^2 = r^2.

It becomes obvious that h = 0, k = 3 and r = 2. The center is at (0, 3).