Answer:
![2(x+4)(x+2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/sl802mw3bw02zlz68uxzzqkvmz4u59ym0j.png)
Explanation:
We can start with the observation that every coefficent in the quadratic
is a multiple of 2. Factoring out the 2, our expression becomes
. Let's focus on the second term,
. To factor this, we want to find two numbers that multiply to 8 and add to 6. 4 · 2 = 8 and 4 + 2 = 6, so we can use that fact to split the middle term and factor the quadratic completely:
![x^2+6x+8\\=x^2+2x+4x+8\\=x(x+2)+4(x+2)\\=(x+4)(x+2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gtqlws3ptnvzzatrj2ywu3jwupsx8lytq3.png)
Putting that back with the 2 we factored out earlier, our fully factored function is
![2(x+4)(x+2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/sl802mw3bw02zlz68uxzzqkvmz4u59ym0j.png)