Question

A pendulum is raised to a height of 0.3m above its lowest point and released. What is the velocity of the pendulum at its lowest point? Assume no air resistance.

Answer 1

v = 2,425 m / s

Step-by-step explanation:

A simple pendulum has anergy stored at the highest point of the path and this energy is conserved throughout the movement.

highest point

Em₀ = U = m g y

lowest point

`Em_(f)` = K = ½ m v²

Em₀ = Em_{f}

mg y = ½ m v²

v = √ 2gy

let's calculate

v = √ (2 9.8 0.3)

v = 2,425 m / s