Question

50 POINTS NO LINKS

An object is launched at 39.2 meters per second (m/s) from a 42.3-meter tall platform. The equation for the objects height s at time t seconds after launch is s(t)=-4.9t^2+39.2t+42.3, where s is in meters. Create a table of values and graph the function. Approximately what is the maximum height of the object?

Answer 1

Convert into vertex form y=a(x-h)²+k

• y=-4.9t²+39.2t+42.3

After calculating

• y=-4.9(x-39.2)²+42.3

Vertex at

• (39.2,42.3)

Max height=42.3m

Graph attached