Question

Mg + 2H20 + Mg(OH)2 + H2 + 353kJ

If a single FRH has 6.Ogof magnesium, Mg, how many grams of water must

be added to react with it completely?

Answer 1

`m_(H_2O)=8.9g`

Step-by-step explanation:

Hello,

Based on the given reaction, since magnesium and water are in a 1:2 molar ratio at the reactants, we must apply the following stoichiometric factors to compute the complete reaction of the 6.0 g of magnesium:

`m_(H_2O)=6.0gMg*(1molMg)/(24.305 gMg)*(2molH_2O)/(1molMg) *(18gH_2O)/(1molH_2O) \\\\m_(H_2O)=8.9g`

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