Question

4. What is the specific heat of iron, if it requires 1050 J of heat energy to raise the temperature of

220,0 g of iron from 10.0.C to 20.4.C?

Answer 1

0.4589 J g^-1 K^-1 IS THE SPECIFIC HEAT OF IRON.

Step-by-step explanation:

Specific heat of iron can be calculated using the heat of reaction formulae

Heat = mass * specific heat * ( T2-T1)

H = m c (T2-T1)

c = H / m * (T2-T1)

H = 1050 J

m = 220.0 g

T2 = 20.4 ° C = 20.4 + 273 = 293.4 K

T1 = 10.0 °C = 10 + 273 K = 283 K

so therefore:

c = 1050 / 220 * ( 293.4 - 283) K

c = 1050 / 220 * 10.4

c = 1050 / 2288

c = 0.4589 J g^-1 K^-1

The specific heat capacity of iron is 0.4589 J g^-1 K^-1

Answer 2

0.4589J/g°C

Step-by-step explanation:

Heat energy = 1050J

Mass of iron = 220.0g

Initial temperature (T1) = 10°C

Final temperature (T2) = 20.4°C

Heat energy = mc∇T

Q = mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity of the substance

∇T = change in temperature = T2 - T1

Q = m×c×(T2 - T1)

1050 = 220 × c ×(20.4 - 10)

1050 = 220c × (10.4)

1050 = 2288c

c = 1050 / 2288

C = 0.4589J/g°C

The specific heat capacity of iron is 0.4589J/g°C