1 Answer

Lukeck · Answer 1 · 2021-10-23T21:10:02+0000

Complete Question

The complete question is shown on the first uploaded image

Answer:

1

$A_1 = 67.58 \ in^2$

2

$A_2 =415.4 \ ft^2$

3

$A_3 = 8.48 \ cm^2$

4

$A_4 = 480.38 \ m^2$

Explanation:

Generally the area of a sector is mathematically represented as

$A = (\theta)/(360) * \pi r^2$

Now at
r_1 = 11 in and
$\theta_1 = 64^o$

A_1 = (64)/(360) * 3.142 * 11^2

$A_1 = 67.58 \ in^2$

Now at
r_2 = 20 ft in and
$\theta_2 = 119 ^o$

A_2 = (119)/(360) * 3.142 * 20^2

$A_2 =415.4 \ ft^2$

Now at
r_3 = 6.5 cm and
$\theta_3 = 23 ^o$

A_3 = (23)/(360) * 3.142 * 6.5 ^2

$A_3 = 8.48 \ cm^2$

Now at
r_4 = 14.2 m and
$\theta_4 = 360 -87 = 273 ^o$

A_4 = (273)/(360) * 3.142 * 14.2^2

$A_4 = 480.38 \ m^2$

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