Question

I. GIVEN TRIANGLE POR, DETERMINE THE FOLLOWING.

please help me out with this ​

Answer 1

34

Explanation:

122

Answer 2

This is a lengthy question ill go through all the formulas

This is a right triangle which means u can use pythagorean theorem to find QP

formula :

`a^(2) +b^(2) =c^(2)`

Note that
`c^(2)` is always the hypotenuse(the hyp is always opposite to ninety degrees)

so lets substitute

=>
`a^(2) +17^(2) =28^(2)`

=>
`a^(2) +289 =784`

subtract 289 both sides

`= > a^(2)=495`

Now square root both

`√( a)^(2)=√(495)`

==>
`3√(55)` or 22.2 (answer)

But for the other three u have to use another formula any of sin, tan,cos while using For example angle Q and then use any and do inverse it will be very easy after u know all the formulas of Sin,cos, tan

SOHCAHTOA

^

Thats an acronym for the formula

Sin= Opposite/ hyp

Cos= Adjustent/Hyp

Tan= Opposite/Adjustent