Question

Given the following reaction:

2 KCIO3
-->2 KCl + 302
How many moles of KCl will be produced from 89.0 g of KCIO,?​

Answer 1

.72 mols of KCl

Explanation:

Read the explanation while looking at the picture.

We start with 89g because it's what they give us:

89g of KCIO3 will cancel out with 123g of KCIO3 (molar mass)

~Grams of KCIO3 are canceled out.~

That 123g of KCIO3 is the same as 1 mol of KCIO3

Then we use mole to mole ratio:

1 mol of KCIO3 equals 2 mols of KCIO3 -- 2 moles from the equation

The 2 mols of KCIO3 is equal to 2 mols of KCl (from equation)

Multiply the numbers on top. Multiply the numbers on the bottom. Then divide. You get:

`.7235772358`

This sounds confusing. But the picture below is the format.

The SAME COLOR are the ones that cancel out.