Question

How many moles of NaCl are present in 530 ml of a 1.52m NaCl solution

Answer 1

805.6 moles

Step-by-step explanation:

Molarity = 1.52mL

Volume = 530mL

1.52 moles is present in 1mL,

1mL = 0.001L

1.52 moles = 0.001L

X moles = 0.53L

X = (1.52 × 0.53) / 0.001

X = 805.6moles

805.6moles is present in 530mL or 0.52L