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The sum of three consecutive numbers is greater than 40. The inequality that represents this is x + x + 1 + x + 2 > 40. Which values of x hold true for the inequality?

User Lmsasu
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1 Answer

4 votes

Answer:

All integers greater than 12 (13 onwards) satisfy the inequality

Explanation:

x + x + 1 + x + 2 > 40.

3x + 3 > 40

3x > 37

x > 12.3333

All integers greater than 12 (13 onwards) satisfy the inequality

User Dhiraj Wakchaure
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