Answer:Yes
Explanation:
Given
Suppose side length of cube is a
If we dilate the cube using a scale factor of 2
Side length becomes 2a
and the surface area becomes
![=6(\text{side length})^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ntb0zlk7ljbabvr43141joek6ocr984h6m.png)
Surface area
![=6(2a)^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ab7tfc45q4li15orwe40qadb3qgpcztw47.png)
Surface area
![=4* 6(a)^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cg97oyouk3tqnhfcieuwx9uczociw5y7c5.png)
Thus surface area multiplied by a factor of 4
Now for volume
![V=(\text{side length })^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/od5exnux4wpaemi60gx9nv3uoz8mh2byot.png)
![V=(2a)^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ca7gwnf59ay09cqzjjeds4jz3ntmqv00ap.png)
![V=8(a^3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3xxy7f4fmm1d8lzr2o3guhhci5haskz9ah.png)
Therefore volume is multiplied by a factor of 8
Therefore the above statements make sense