Answer:
The age of the spear head is of 1938 yers.
Explanation:
The amount of carbon 14 after years is given by the following equation:
![Q(t) = Q(0)e^(-rt)](https://img.qammunity.org/2021/formulas/mathematics/college/xc1aaedgzeg9inpyh4j52i5ut1oda7uy9w.png)
In which Q(0) is the initial amount and r is the decay rate.
The half life of carbon 14 is 5700 years.
This means that
![Q(5700) = 0.5Q(0)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9vu5g2hggfejnurfaqyr78go9kzedps41b.png)
So
![Q(t) = Q(0)e^(-rt)](https://img.qammunity.org/2021/formulas/mathematics/college/xc1aaedgzeg9inpyh4j52i5ut1oda7uy9w.png)
![0.5Q(0) = Q(0)e^(-5700r)](https://img.qammunity.org/2021/formulas/mathematics/high-school/2zuutank6sg103hkx4ps67bxbpuqfohoui.png)
![e^(-5700r) = 0.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/36skgebat3lc2t2gk24i352rwd15cr50uz.png)
![\ln{e^(-5700r)} = ln(0.5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hiypg9kp6wsgd6ccpciinrw5pcods9zru2.png)
![-5700r = ln(0.5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d83ba83uy1dirnpt79sl4i9fr99plkw153.png)
![5700r = -ln(0.5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/k2dy8rbvv9um33qv6uja2ygy06622dkrcq.png)
![r = -(ln(0.5))/(5700)](https://img.qammunity.org/2021/formulas/mathematics/high-school/2h4pbb761gyavcby60026z8egio296qcfg.png)
![r = 0.00012160476](https://img.qammunity.org/2021/formulas/mathematics/high-school/zcvj2hw4qnd2v4mhqaupqfmymypkzrbqvs.png)
So
![Q(t) = Q(0)e^(-0.00012160476t)](https://img.qammunity.org/2021/formulas/mathematics/high-school/impml2yd6mb8j23v6e3m5zq3ondih8coeh.png)
We have to find:
t for which Q(t) = 0.79Q(0). So
![Q(t) = Q(0)e^(-0.00012160476t)](https://img.qammunity.org/2021/formulas/mathematics/high-school/impml2yd6mb8j23v6e3m5zq3ondih8coeh.png)
![0.79Q(0) = Q(0)e^(-0.00012160476t)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5a1pbentziv4p571eg7rzh84mda17v9apv.png)
![e^(-0.00012160476t) = 0.79](https://img.qammunity.org/2021/formulas/mathematics/high-school/ztt1c3sd1m26k7rbcd3jxx7okb8s7dgbq8.png)
![\ln{e^(-0.00012160476t)} = ln(0.79)](https://img.qammunity.org/2021/formulas/mathematics/high-school/udhnhj87143dhkf62v015g5up9qe4dr6o5.png)
![-0.00012160476t = ln(0.79)](https://img.qammunity.org/2021/formulas/mathematics/high-school/edtujh7n4ao3a6x58rcc4solvflgwzmcaq.png)
![0.00012160476t = -ln(0.79)](https://img.qammunity.org/2021/formulas/mathematics/high-school/90ssiglsq04fw0pcj5dxp9xqbk513jb28y.png)
![t = (-ln(0.79))/(0.00012160476)](https://img.qammunity.org/2021/formulas/mathematics/high-school/fuo1v3f9826qpn7sjhybsvwdnikinct5mw.png)
![t = 1938.43](https://img.qammunity.org/2021/formulas/mathematics/high-school/unsktq52xb3fndv97wqob7tunjch389qup.png)
Rounding to the nearest year.
The age of the spear head is of 1938 yers.