Question

The equations x minus 3 y = negative 3, 2 x + y = 2, x + 3 y = 3, and 2 x minus y = negative 2 are shown on the graph below. On a coordinate plane, there are 4 lines. Green line goes through (0, 2) and (negative 1, 0). Blue line goes through (0, 2) and (1, 0). Pink line goes through (negative 1.5, 1.5), and (1.5, 0.5). Orange line goes through (negative 1.5, 0.5) and (1.5, 1.5). Which system of equations has a solution of approximately (–0.4, 1.1)? x + 3 y = 3 and 2 x minus y = negative 2 x minus 3 y = negative 3 and 2 x + y = 2 x minus 3 y = negative 3 and 2 x minus y = negative 2 x + 3 y = 3 and 2 x + y =2

Answer 1

A

Explanation:

Answer 2

(A)x+3y=3 and 2x-y=-2

Explanation:

In the attached graph

• Green line is the graph of 2x-y=-2
• Red line is the graph of x-3y=-3
• Orange line is the graph of x+3y=3
• Blue Line is the graph of 2x+y=2

The point of the intersection of the orange and green line has an approximate solution of (-0.4,1.1).

Therefore, the system of equation which has the approximate solution is: x+3y=3 and 2x-y=-2

The correct option is A