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What are the vertices of the hyperbola whose equation is (x+3)^2/4-(y-5)^2/16=1
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What are the vertices of the hyperbola whose equation is (x+3)^2/4-(y-5)^2/16=1

User Jack Satriano
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2 Answers

4 votes

Answer:

Provided below. Hope this helps:))

Explanation:

What are the vertices of the hyperbola whose equation is (x+3)^2/4-(y-5)^2/16=1-example-1
User Gaius Parx
by
4.6k points
4 votes

Answer:

(-5,5) and (-1,5)

Explanation:

second option on edge

User NoChance
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3.7k points
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