Question

What is the solution to In (x2 - 16) = 0?
x=1v17
x= +4
x=+/32

Answer 1

x = ±
`√(17)`

Explanation:

Given

ln(x² - 16) = 0, then

x² - 16 =
`e^(0)` = 1 ( add 16 to both sides )

x² = 17 ( take the square root of both sides )

x = ±
`√(17)`

Answer 2

B.

Explanation:

x²-16 = 0

Adding 16 to both sides

x² = 16

Taking square root on both sides

we get

√x² = √16

x = ± 4

Either,

x=4 OR x= -4