Find the third fourth and eleventh terms of the sequence described by the rule A(n)=-2+(n-1)(5)

Latoyia asked Jun 17, 2023

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Latoyia asked Jun 17, 2023

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7 votes

Answer:

8,13,48

Explanation:

Third = A(3) = -2 + (3-1)(5) = -2 + 10 = 8

Fourth = A(4) = -2 +(4-1)(5) = -2 + 15 = 13

Eleventh = A(11) = -2 + (11-1)(5) = -2 + 50 = 48

Destroyer answered Jun 22, 2023

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