Answer:
The rate at which the horizontal velocity of the ball changes every second is, 19%.
Explanation:
The exponential decay function is given by:
![y=a(1-r)^(t)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ppnx33xhts51iuvbezjs1arubgxvq3midi.png)
Here,
y = final value
a = initial value
r = decay rate
t = time
The relationship between the elapsed time, t, in seconds, since Mustafa threw the ball, and its horizontal velocity, V (t) is:
![V(t)=4\cdot (0.81)^(t)](https://img.qammunity.org/2021/formulas/mathematics/college/knlwyr6z3lrwy4ydlnx36hzi6grvs3fo4g.png)
The expression for the horizontal velocity of the ball represents the exponential decay function.
On comparing the two equations we get:
![1-r=0.81\\r=1-0.81\\r=0.19](https://img.qammunity.org/2021/formulas/mathematics/college/tzmyy6txvt635fw6x42pkhhl98yf66yhy2.png)
Thus, the rate at which the horizontal velocity of the ball changes every second is, 19%.