Question

What temperature in kelvin does 21 of sulfur dioxide occupy if there are 2.5 mol of it at 1.75 atm?

Answer 1

Answer: 179 K

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 1.75 atm

V = Volume of gas = 21 L

n = number of moles = 2.5

R = gas constant =
`0.0821Latm/Kmol`

T = temperature in Kelvin = ?

`T=(PV)/(nR)`

Putting the values , we get :

`T=(1.75atm* 21L)/(2.5* 0.0820 L atm/K mol)=179K`

Thus temperature in kelvin is 179 for 21 L of sulfur dioxide occupy if there are 2.5 mol of it at 1.75 atm