Answer:
(x-1)(x-2)
Explanation:
To factor x^2-3x+2 as (x+a)(x+b) we need to find number a and b such that a+b=-3 ab=2
Summary of above: (−1)+(−2)=−3
So the integers we are looking for are
−1 and −2
Therefore, x^2-3x+2=(x-1)(x-2)
(x+1)(x+2)
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