Question

5. If there is 7.7 moles of gaseous nitric acid at a pressure of 0.09 atm and

at a temperature of 56 OC, what is the volume of the container that the
w
gas is in?

Answer 1

Answer: Thus the volume of the container that the gas is in 2311 L

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 0.09 atm

V = Volume of gas = Volume of container = ?

n = number of moles = 7.7

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`56^0C=(56+273)K=329K`

`V=(nRT)/(P)`

`V=(7.7mol* 0.0821Latm/K mol* 329K)/(0.09atm)=2311L`

Thus the volume of the container that the gas is in 2311 L