Question

How many Liters are in 17.3 moles of Iron?

Answer 1

`V_(Fe)=0.125L`

Step-by-step explanation:

Hello,

In this case, given the moles of iron, we need to use it atomic mass (55.845 g/mol) and density (7.874 g/cm³) in order to firstly convert from moles to grams and secondly from grams to cubic centimetres:

`V_(Fe)=17.6molFe* (55.845gFe)/(1molFe)*(1cm^3)/(7.874gFe)=124.8cm^3`

Finally, we obtain the volume in litres by:

`V_(Fe)=124.8cm^3*(1L)/(1000cm^3) \\\\V_(Fe)=0.125L`

Best regards.

Answer 2

There are 0.12269 Liters of Iron

Step-by-step explanation:

First, by means of the molecular weight equation, the grams of iron corresponding to 17.3 moles can be calculated:

`MW=(mass(grams))/(moles)`

`mass=MW*moles=55.845(g)/(mol) *17.3mol=966.119 g`

Then using the density equation the iron milliters are calculated:

`d=(mass(g))/(volume(mL))`

`volume=(mass)/(density)=(966.119g)/(7.874(g)/(mL) ) =122.69 mL`

Milliliters to liters are converted:

122.69 mL = 0.12269 L of Iron.