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Find one value of x that is a solution to the equation:
(x - 2)^2 – 6(x - 2) + 5 = 0
x =​

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Answer:

3 or 7

Let (x-2) be a

a^2 - 6a + 5 = 0

(a-5)(a-1) = 0

a=5 or a=1

x-2=5 or x-2=1

x=7 or x=3

User Peter Morris
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