PH of a 4.5x10-6 M solution of HCl.

Yoohoo asked Mar 17, 2023

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Yoohoo asked Mar 17, 2023

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13 votes

$\text{pH} = -\log[H^(+)] = - \log[4,5 * 10^(-6)] = 5.34$

Lukeocom answered Mar 23, 2023

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