Question

Which number is a solution of a² +4= 6a – 1?
07
6
7
8

Answer 1

a=1 or a=5

Explanation:

`a^(2)`+4=6a−1

Step 1: Subtract 6a-1 from both sides.

`a^(2)`+4−(6a−1)=6a−1−(6a−1)

`a^(2)`−6a+5=0

Step 2: Factor left side of equation.

(a−1)(a−5)=0

Step 3: Set factors equal to 0.

a−1=0 or a−5=0

a=1 or a=5

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