Question

A cooker has a resistance of 100 Ohms and a power rating of 0.5KW. What potential difference would be needed to run the

cooker​

Answer 1

The potential difference is 224V .

Step-by-step explanation:

Given that the formula of power is P = I×V and formula of voltage is V = I×R where both I represents current.

Given that the formula of power is P = I×V and formula of voltage is V = I×R where both I represents current. Then you have to use voltage formula to make I the subject :

`v = i * r`

`i = (v)/(r)`

So that you can substitute it into the formula of power :

`p = i * v`

`p = (v)/(r) * v`

`p = \frac{ {v}^(2) }{r}`

Let p = 500W,

Let r = 100Ω,

`500 = \frac{ {v}^(2) }{100}`

`500 * 100 = {v}^(2)`

`{v}^(2) = 50 \: 000`

`v = √(50000)`

`v = 224 \: \: (3s.f)`