1 Answer

Eywu · Answer 1 · 2021-07-14T01:07:49+0000

Answer:a

Explanation:

Given

$f(x)=1.6^x\sin 3x$

we know that value of sin function vary between
$-1\ \text{to}\ 1$

i.e. it take finite value so

$\lim \limits_(x\rightarrow -\infty)f(x)=\lim \limits_(x\rightarrow -\infty)\quad 1.6^x\sin 3x$

when
$x\rightarrow -\infty$

then
$1.6^x\rightarrow 0$

therefore

$\lim \limits_(x\rightarrow -\infty)\quad 1.6^x\sin 3x=0$

option a is correct

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