Question

A line passes through the point (6,-6) and has a slope of 3/2. Write a equation in point-slope form for this line

Answer 1

`y=(3)/(2)x-15`

Explanation:

The point-slope equation is
`y-y_(1) =m(x-x_(1) )`

Here our m is our slope which is
`(3)/(2)` and our
`(x_(1),y_(1))` point is (6, -6)

Plugging in these values to our equation gives us

y - (-6) =
`(3)/(2)`(x - 6) → distribute the negative to the -6 on the left side and then distribute the
`(3)/(2)` to the x term and the -6 on the right side → y + 6 =
`(3)/(2)x` - 9 → then subtract the 6 from both sides →
`y=(3)/(2) x-15`

Answer 2

Answer:
`y+6=(3)/(2) (x-6)`

Explanation:

use the equation
`y-y_(1) =m(x-x_(1))`

we know the slope, y, and x, so plug in

`y-(-6)=(3)/(2) (x-(6))`

`y+6=(3)/(2) (x-6)`