Question

Given the following equation: Ca(OH)2 + 2HNO3 --> 2 H2O

+ Ca(NO3)2
How many moles of water are produced when 2.27
moles of calcium hydroxide reacts with excess nitric
acid?
Please include your units and round to two decimal places.

Answer 1

Answer: 4.45 moles of
`H_2O` will be produced.

Step-by-step explanation:

The balanced chemical equation:

`Ca(OH)_2+2HNO_3\rightarrow 2H_2O+Ca(NO_3)_2`

As nitric acid is the excess reagent, calcium hydroxide is the limiting reagent as it limits the formation of product.

According to stoichiometry :

1 mole of
`Ca(OH)_2` produce = 2 moles of
`H_2O`

Thus 2.27moles of
`Ca(OH)_2` will produce =
`(2)/(1)* 2.27=4.54moles` of
`H_2O`

Thus 4.45 moles of
`H_2O` will be produced.