We have been given image of circle that passes through point
. We are asked to find the radius of the circle.
First of all, we will find the center of the circle.
We can see that center of circle is at point
.
Now we will use equation of circle to find radius.
, where, point (h,k) represents center of circle and r represents radius of circle.
Now we will substitute the coordinates of point
and coordinates of center
and solve for r as:




Switch sides:

Now we will take positive square root on both sides:


Therefore, radius of circle will be
and center is at point
.